Exercises VI

1-bit and 2-bit Characters

原题链接

解法：greedy

class Solution {
public:
    bool isOneBitCharacter(vector<int>& bits) {
        int i=bits.size()-2;
        while(i>=0&&bits[i]>0) i--;
        return (bits.size()-i)%2==0;
    }
};

Can Place Flowers

原题链接